How much energy is required to change a 35 g ice cube from ice at -40°C to steam at 120°C? - ice 35 flasher instructionalvideo
How much energy required to change an Ice Cube 35 grams of ice at -40 ° C to steam at 120 ° C?
(Answer in joules)
Saturday, January 30, 2010
Ice 35 Flasher Instructionalvideo How Much Energy Is Required To Change A 35 G Ice Cube From Ice At -40°C To Steam At 120°C?
2 comments:
Q (heat) = mass (m) XC (specific heat) x T (temperature change)
m = 35 x 0001 = 0035 kg
Joules C = 10 4.2 x 3
T = 120 + 40 = 160
Q = 0.035 x 160 x (4.2 x 10 ^ 3)
= 23,520 Joules
1 calorie raises 1 gram of water 1 ° C.
Total Energy = mass * change in temperature (120 - -40) * 35 = 5600 cal
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